Topic: Algebra II help P-L-E-A-S-E-**********
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wildfirefxxnot-such-a-newbie  total posts: 23 since: Feb 2008
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 Mar 30, 08 at 12:49pm
Algebra II help P-L-E-A-S-E-**********
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I need help with my Algebra II please. *STORY PROBLEMS* heck yeah! Sorry, lol. Well, 8 of the 10 are story problems.
FIND THE NUMBER DESCRIBED #2-4: 2. 12 is 3/5 of 10/21 of the number. DONE WITH!
4. 75% of 60% of the number is 36. DONE WITH!
6. An old conveyor belt takes 21 h to move one day's coal output from the mine to a rail line. A new belt can do it in 15 h. How long does it take when both are used at the same time?
8. How much water must be evaporated from a 300 L tank of a 2% solution to obtain a 5% solution?
10. Pam jogged up a hill at 6 km/h and then jogged back down at 10 km/h. How many kilometers did she travel in all if her total jogging time was 1 h 20 min.?
12. Lina Chen invested $24,000, part at 8% and the rest at 7.2%. How much did she invest at each rate if her income from the 8% investment is two thirds that of the 7.2% investment?
14. How much of an 18% solution of sulfuric acid should be added to 360 mL of a 10% solution to obtain a 15% solution?
16. Pipes A and B can fill a storage tank in 8 h and 12 h, respectively. With the tank empty, pipe A was turned on at noon, and then pipe B was turned on at 1:30 P.M. At what time was the tank full?
18. An elevator went from the bottom to the top of a tower at an average speed of 4 m/s, remained at the top for 90 s, and then returned to the bottom at 5 m/s. If the total elapsed time was 4.5 min, how high is the tower?
20. A car radiator is filled with 5 L of a 25% antifreeze solution. How many liters must be drawn off and replaced by a 75% antifreeze solution to leave the radiator filled with a 55% antifreeze solution?
Please show the work to generate these answers and I will try to work a few of these out myself. Thank you all for your help.
(is problem #18: 810 meters high?) (is problem #10: 10.6666666666666 km? (10.6 with a bar over the 6 kilometers)
This message was edited by wildfirefxx on Mar 30 2008.
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metafor
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 Mar 30, 08 at 7:42pm
re: Algebra II help P-L-E-A-S-E-**********
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10. 10 km. The average speed is total distance divided by total time; it can also be calculated by finding the average of all the speeds. From this,
(6 km/h + 10 km/h)/2 = D / 1.25 h (16 km/h)/2 = D / 1.25 h 8 km/h = D / 1.25 h 1.25 h(8 km/h) = D 10 km = D
18. No. Remember that time is equal to distance divided by speed. Since the same distance is travelled during both trips, the equation would be
[4.5(60)] - 90 = d/4 + d/5,
[4.5(60)] - 90 representing the total time of both trips, in seconds (180: 4.5 minutes = 270 seconds, but we have to subtract the 90 seconds where the elevator did not move), d/4 and d/5 representing the height of the tower (d), in meters, divided by the speed of each trip (4 and 5, respectively), in meters per second. Thus, we have
180 = d/4 + d/5 180 = 5d/20 + 4d/20 180 = 9d/20 3,600 = 9d 400 = d.
Checking our answer through substitution, we get that
180 = 400/4 + 400/5 180 = 100 + 80 180 = 180.
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